0,25x^2-0,36=0

Solution for 0,25x^2-0,36=0 equation:

0.25x^2-0.36=0

a = 0.25; b = 0; c = -0.36;
Δ = b2-4ac
Δ = 02-4·0.25·(-0.36)
Δ = 0.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.36}}{2*0.25}=\frac{0-\sqrt{0.36}}{0.5}
=-\frac{\sqrt{}}{0.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.36}}{2*0.25}=\frac{0+\sqrt{0.36}}{0.5}
=\frac{\sqrt{}}{0.5}
$